Hi
Im trying to create a job folder in the assemble job command from file names.
So if I have 4 files called-
006_12XX_NZ_999999.pdf
007_12XX_NZ_999999.pdf
006_12XX_AU_999999.pdf
007_12XX_AU_999999.pdf
I can use the before and after variables to use the 999999 job number to create folders with the after _NZ_ command, is there any way within the same argument to add an 'or' operator for _AU_ files?
Thanks
Ed
Folder name from files
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Folder name from files
Try just adding it as a second entry - if Switch cannot create the variable it just seems to leave it blank. I do a similar thing for files from 3 sources:
[Metadata.Text:Path="/jobInfo/Customer",Dataset="Xml",Model=XML][Metadata.Text:Path="/jobInfo/Customer",Dataset="jobticket",Model=XML][Metadata.Text:Path="/XMLSTINGRAYInJobReport/Customer",Dataset="Xml",Model=XML]
/
[Metadata.Text:Path="/jobInfo/Reference",Dataset="jobticket",Model=XML][Metadata.Text:Path="/jobInfo/Reference",Dataset="Xml",Model=XML][Metadata.Text:Path="/XMLSTINGRAYInJobReport/Reference",Dataset="Xml",Model=XML]
(Building a "Customer/Reference" path)
[Metadata.Text:Path="/jobInfo/Customer",Dataset="Xml",Model=XML][Metadata.Text:Path="/jobInfo/Customer",Dataset="jobticket",Model=XML][Metadata.Text:Path="/XMLSTINGRAYInJobReport/Customer",Dataset="Xml",Model=XML]
/
[Metadata.Text:Path="/jobInfo/Reference",Dataset="jobticket",Model=XML][Metadata.Text:Path="/jobInfo/Reference",Dataset="Xml",Model=XML][Metadata.Text:Path="/XMLSTINGRAYInJobReport/Reference",Dataset="Xml",Model=XML]
(Building a "Customer/Reference" path)